Optimal. Leaf size=72 \[ \frac {\log \left (a+b e^{c-d x}\right )}{a^3 d}+\frac {x}{a^3}-\frac {1}{a^2 d \left (a+b e^{c-d x}\right )}-\frac {1}{2 a d \left (a+b e^{c-d x}\right )^2} \]
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Rubi [A] time = 0.04, antiderivative size = 72, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, integrand size = 14, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.143, Rules used = {2282, 44} \[ -\frac {1}{a^2 d \left (a+b e^{c-d x}\right )}+\frac {\log \left (a+b e^{c-d x}\right )}{a^3 d}+\frac {x}{a^3}-\frac {1}{2 a d \left (a+b e^{c-d x}\right )^2} \]
Antiderivative was successfully verified.
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Rule 44
Rule 2282
Rubi steps
\begin {align*} \int \frac {1}{\left (a+b e^{c-d x}\right )^3} \, dx &=-\frac {\operatorname {Subst}\left (\int \frac {1}{x (a+b x)^3} \, dx,x,e^{c-d x}\right )}{d}\\ &=-\frac {\operatorname {Subst}\left (\int \left (\frac {1}{a^3 x}-\frac {b}{a (a+b x)^3}-\frac {b}{a^2 (a+b x)^2}-\frac {b}{a^3 (a+b x)}\right ) \, dx,x,e^{c-d x}\right )}{d}\\ &=-\frac {1}{2 a d \left (a+b e^{c-d x}\right )^2}-\frac {1}{a^2 d \left (a+b e^{c-d x}\right )}+\frac {x}{a^3}+\frac {\log \left (a+b e^{c-d x}\right )}{a^3 d}\\ \end {align*}
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Mathematica [A] time = 0.09, size = 62, normalized size = 0.86 \[ \frac {\frac {b e^c \left (4 a e^{d x}+3 b e^c\right )}{\left (a e^{d x}+b e^c\right )^2}+2 \log \left (a e^{d x}+b e^c\right )}{2 a^3 d} \]
Antiderivative was successfully verified.
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fricas [A] time = 0.44, size = 132, normalized size = 1.83 \[ \frac {2 \, b^{2} d x e^{\left (-2 \, d x + 2 \, c\right )} + 2 \, a^{2} d x - 3 \, a^{2} + 2 \, {\left (2 \, a b d x - a b\right )} e^{\left (-d x + c\right )} + 2 \, {\left (2 \, a b e^{\left (-d x + c\right )} + b^{2} e^{\left (-2 \, d x + 2 \, c\right )} + a^{2}\right )} \log \left (b e^{\left (-d x + c\right )} + a\right )}{2 \, {\left (2 \, a^{4} b d e^{\left (-d x + c\right )} + a^{3} b^{2} d e^{\left (-2 \, d x + 2 \, c\right )} + a^{5} d\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [A] time = 0.21, size = 71, normalized size = 0.99 \[ \frac {\frac {2 \, {\left (d x - c\right )}}{a^{3}} + \frac {2 \, \log \left ({\left | b e^{\left (-d x + c\right )} + a \right |}\right )}{a^{3}} - \frac {2 \, a b e^{\left (-d x + c\right )} + 3 \, a^{2}}{{\left (b e^{\left (-d x + c\right )} + a\right )}^{2} a^{3}}}{2 \, d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [A] time = 0.01, size = 79, normalized size = 1.10 \[ -\frac {1}{2 \left (b \,{\mathrm e}^{-d x +c}+a \right )^{2} a d}-\frac {1}{\left (b \,{\mathrm e}^{-d x +c}+a \right ) a^{2} d}+\frac {\ln \left (b \,{\mathrm e}^{-d x +c}+a \right )}{a^{3} d}-\frac {\ln \left ({\mathrm e}^{-d x +c}\right )}{a^{3} d} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [A] time = 0.90, size = 88, normalized size = 1.22 \[ -\frac {2 \, b e^{\left (-d x + c\right )} + 3 \, a}{2 \, {\left (2 \, a^{3} b e^{\left (-d x + c\right )} + a^{2} b^{2} e^{\left (-2 \, d x + 2 \, c\right )} + a^{4}\right )} d} + \frac {d x - c}{a^{3} d} + \frac {\log \left (b e^{\left (-d x + c\right )} + a\right )}{a^{3} d} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [B] time = 3.65, size = 124, normalized size = 1.72 \[ \frac {\frac {x}{a}+\frac {b^2\,x\,{\mathrm {e}}^{2\,c-2\,d\,x}}{a^3}+\frac {2\,b\,x\,{\mathrm {e}}^{c-d\,x}}{a^2}+\frac {3\,b^2\,{\mathrm {e}}^{2\,c-2\,d\,x}}{2\,a^3\,d}+\frac {2\,b\,{\mathrm {e}}^{c-d\,x}}{a^2\,d}}{a^2+2\,{\mathrm {e}}^{c-d\,x}\,a\,b+{\mathrm {e}}^{2\,c-2\,d\,x}\,b^2}+\frac {\ln \left (a+b\,{\mathrm {e}}^{-d\,x}\,{\mathrm {e}}^c\right )}{a^3\,d} \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [A] time = 0.20, size = 78, normalized size = 1.08 \[ \frac {- 3 a - 2 b e^{c - d x}}{2 a^{4} d + 4 a^{3} b d e^{c - d x} + 2 a^{2} b^{2} d e^{2 c - 2 d x}} + \frac {x}{a^{3}} + \frac {\log {\left (\frac {a}{b} + e^{c - d x} \right )}}{a^{3} d} \]
Verification of antiderivative is not currently implemented for this CAS.
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